(x-3)/(x^2+1)=2

Solution for (x-3)/(x^2+1)=2 equation:

(x-3)/(x^2+1)=2

We move all terms to the left:

(x-3)/(x^2+1)-(2)=0


Domain of the equation: (x^2+1)!=0

We move all terms containing x to the left, all other terms to the right

x^2!=-1

x^2!=-1/

x^2!=√-1/

x!=NAN

x∈R


We multiply all the terms by the denominator


(x-3)-2*(x^2+1)=0

We multiply parentheses

-2x^2+(x-3)-2=0

We get rid of parentheses

-2x^2+x-3-2=0

We add all the numbers together, and all the variables

-2x^2+x-5=0

a = -2; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-2)·(-5)
Δ = -39
Delta is less than zero, so there is no solution for the equation